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2 Ways to remove whitespaces from String in Java? Example Tutorial You can remove blanks for whitespaces from a Java String by using the trim() method of java.lang.String class of JDK API. Unlike SQL Server which have LTRIM() and RTRIM() methods to remove whitespace from String, Java doesn't have ltrim() and rtrim() methods to trim white spaces from left and right, instead it just have a trim() method which removes all spaces from String including space at the beginning and at the end. Since String is Immutable in Java, it's worth noting that this method return a new String if original String contains space either at beginning or end, otherwise it will return the same String back.  --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to Compare Two Strings Without Case Sensitivity in Java? Example How to Compare Two Strings Without Case Sensitivity in Java Java provides several ways to compare strings without taking case sensitivity into account. In this article, we'll explore different methods to perform case-insensitive string comparisons in Java. Method Use Case Efficiency equalsIgnoreCase() Checking equality High compareToIgnoreCase() Ordering comparison High String.CASE_INSENSITIVE_ORDER Sorting collections High equals() + toUpperCase() Not recommended Low 1. Using equalsIgnoreCase() The equalsIgnoreCase() method This method is ideal for checking if two strings are equal without considering their case. It returns true if both strings contain the same characters, regardless of their case. String str1 = "Hello"; String str2 = "hello"; boolean isEqual = str1.equalsIgnoreCase(str2); // Returns true 2. Using compareToIgnoreCase() The compareToIgnoreCase() method Use this method when you want to check which string is greater or smaller, or to find out their relative ordering in lexicographical or alphabetical order, without considering case. String str1 = "Apple"; String str2 = "banana"; int result = str1.compareToIgnoreCase(str2); // Returns a negative value 3. Using String.CASE_INSENSITIVE_ORDER The String.CASE_INSENSITIVE_ORDER comparator This comparator is useful for sorting a list of strings in case-insensitive order. List fruits = Arrays.asList("Apple", "banana", "Cherry"); Collections.sort(fruits, String.CASE_INSENSITIVE_ORDER); // Result: [Apple, banana, Cherry] 4. Using equals() + toUpperCase() Combining equals() and toUpperCase() This is a tricky way to compare two strings in Java in a case-insensitive manner. First, convert both strings to uppercase, then compare them using equals(). String str1 = "Hello"; String str2 = "hello"; boolean isEqual = str1.toUpperCase().equals(str2.toUpperCase()); // Returns true Note: This method is not recommended as it creates new String objects, which can be inefficient for large-scale comparisons. Conclusion When comparing strings without case sensitivity in Java, it's generally best to use the built-in methods like equalsIgnoreCase() for equality checks and compareToIgnoreCase() for ordering comparisons.  These methods are optimized and provide clear, readable code. For sorting collections of strings, the String.CASE_INSENSITIVE_ORDER comparator is an excellent choice. Remember, all these methods compare strings in lexicographical order. Choose the method that best fits your specific use case to ensure efficient and accurate string comparisons in your Java applications. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to get first and last character of String in Java - Example You can get the first and last character of a String using the charAt() method in Java. This method accepts an integer index and returns the corresponding character from String. Since Java String is backed by an array, their index is also zero-based, which means the first character resides at index zero, and the last character is at index, length-1, where length is the number of characters in the String. You can get the length of the String by calling the length() method. The charAt() method is not defined on java.lang.String class, but on its super interface java.lang.CharSequence, hence it will also work for StringBuffer and StringBuilder. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to Remove First and Last Character of String in Java - Example Tutorial You can use the substring() method of java.lang.String class to remove the first or last character of String in Java. The substring() method is overloaded and provides a couple of versions that allows you to remove a character from any position in Java. Alternatively, you can convert String to StringBuffer or StringBuilder and then use its remove() method to remove the first or last character. Both StringBuffer and StringBuilder provides a convenient deleteCharAt(int index) method which removes a character from the corresponding index. You can use this method to remove both first and last characters from String in Java. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to compare two String in Java - String Comparison Example String comparison is a common programming task and Java provides several way to compare two String in Java. String is a special class in Java, String is immutable and It’s used a lot in every single Java program starting from simple test to enterprise Java application. In this Java String compare tutorial we will see different ways to compare two String in Java and find out how they compare String and when to use equals() or compareTo() for comparison etc. Here are four examples of comparing String in Java 1) String comparison using equals method 2) String comparison using equalsIgnoreCase method 2) String comparison using compareTo method 4) String comparison using compareToIgnoreCase method --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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Top 15 Java String interview Question Answers for 3 to 5 Years Experienced 10 Java String interviews Question answers String interview questions in Java is one of Integral part of any Core Java or J2EE interviews. No one can deny the importance of String and how much it is used in any Java application irrespective of whether it's core Java desktop application, web application, Enterprise application or Mobile application. The string is one of the fundamentals of Java programming language and correct understanding of String class is a must for every Java programmer. What makes String interview questions in Java even more interesting is the special status of String in terms of features and privileges it has like the + operator is kind of overloaded to perform String concatenation despite the fact that Java does not support operator overloading. There is a separate String pool to store String literal etc. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to check if a String is numeric in Java? Use isNumeric() or isNumber() Example In day-to-day programming, you often need to check if a given string is numeric or not. It's also a good interview question but that's a separate topic of discussion. Even though you can use Regular expression to check if the given String is empty or not, as shown here, they are not full proof to handle all kinds of scenarios, which common third-party libraries like Apache commons-lang will handle e.g. hexadecimal and octal String. Hence, In the Java application, the simplest way to determine if a String is a number or not is by using the Apache Commons lang's isNumber() method, which checks whether the String is a valid number in Java or not. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to check if String contains another SubString in Java? contains() and indexOf() example You can use contains(), indexOf() and lastIndexOf() method to check if one String contains another String in Java or not. If a String contains another String then it's known as a substring. The indexOf() method accepts a String and returns the starting position of the string if it exists, otherwise, it will return -1. For example "fastfood".indexOf("food") will return 4 but "fastfood".indexOf("Pizza") will return -1. This is the easiest way to test if one String contains another substring or not. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to replace a substring in Java? String replace() method Example Tutorial You can replace a substring using replace() method in Java. The String class provides the overloaded version of the replace() method, but you need to use the replace(CharSequence target, CharSequence replacement). This version of the replace() method replaces each substring of this string (on which you call the replace() method) that matches the literal target sequence with the specified literal replacement sequence. For example, if you call "Effective Java".replace("Effective", "Head First") then it will replace "Effective" with "Head First" in the String "Effective Java". Since String is Immutable in Java, this call will produce a new String "Head First Java". --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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StringTokenizer Example in Java with Multiple Delimiters - Example Tutorial StringTokenizer is a legacy class for splitting strings into tokens. In order to break String into tokens, you need to create a StringTokenizer object and provide a delimiter for splitting strings into tokens. You can pass multiple delimiters e.g. you can break String into tokens by, and: at the same time. If you don't provide any delimiter then by default it will use white-space. It's inferior to split() as it doesn't support regular expression, also it is not very efficient. Since it’s an obsolete class, don't expect any performance improvement either. On the hand split() has gone some major performance boost on Java 7, see here to learn more about splitting String with regular expression. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to remove all special characters from String in Java? Example Tutorial You can use a regular expression and replaceAll() method of java.lang.String class to remove all special characters from String. A special character is nothing but characters like - ! #, %, etc. Precisely, you need to define what is a special character for you. Once you define that you can use a regular expression to replace those characters with empty String, which is equivalent to removing all special characters from String. For example, suppose, your String contains some special characters e.g. "Awesome!!!" and you want to remove those !!! to reduce some excitement, you can use replaceAll("!", "") to get rid of all exclamation marks from String. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to convert String or char to ASCII values in Java - Example Tutorial You can convert a character like 'A' to its corresponding ASCII value 65 by just storing it into a numeric data type like byte, int, or long as shown below : int asciiOfA = (int) 'A'; Here casting is not necessary, simply assigning a character to an integer is enough to store the ASCII value of character into an int variable, but casting improves readability. Since ASCII is a 7-bit character encoding, you don't even need an integer variable to store ASCII values, byte data type in Java, which is 8 bits wide is enough to store the ASCII value of any character.  So you can also do like this : byte asciiOfB = 'B'; // assign 66 to variable --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to String Split Example in Java - Tutorial Java String Split Example I don't know how many times I needed to Split a String in Java. Splitting a delimited String is a very common operation given various data sources e.g CSV file which contains input string in the form of large String separated by the comma. Splitting is necessary and Java API has great support for it. Java provides two convenience methods to split strings first within the java.lang.String class itself: split (regex) and other in java.util.StringTokenizer. Both are capable of splitting the string by any delimiter provided to them. Since String is final in Java every split-ed String is a new String in Java. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How to use String in switch case in Java with Example Have you ever feel that String should be used in switch cases like int and char? JDK 7 has made an important enhancement in their support of String, now you can use String in switch and case statements, No doubt String is the most widely used type in Java, and in my opinion, they should have made this enhancement long back when they provided support for enum in java and allowed enum to be used in a switch statement.  --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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How SubString method works in Java - Memory Leak Fixed in JDK 1.7 Substring method from the String class is one of the most used methods in Java, and it's also part of an interesting String interview question e.g. How substring works in Java or sometimes asked as to how does substring creates memory leak in Java. In order to answer these questions, your knowledge of implementation details is required. Recently one of my friends was drilled on the substring method in Java during a Java interview, he was using the substring() method for a long time, and of course, all of us has used this, but what surprises him was the interviewer's obsession on Java substring, and deep-dive till the implementation level. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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Why character array is better than String for Storing password in Java? Example Why character array is better than String for storing a password in Java was a recent question asked to one of my friends in a java interview. he was interviewing for a Technical lead position and has over 6 years of experience. Both Character array and String can be used to store text data but choosing one over the other is a difficult question if you haven't faced the situation already. But as my friend said any question related to String must have a clue on a special property of Strings like immutability and he used that to convince the interviewer. here we will explore some reasons why should you use char[] for storing passwords than String. --- Java, Unix, Tibco RV and FIX Protocol Tutorial

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